+9665 Square the second equation.
(x+y)^2=9
x^2 + 2xy + y^2 = 9
Substitute the first equation to this.
2xy + 9 = 9
2xy = 0
xy = 0
First let x = 0
0+y = 3
y = 3
A solution is (0, 3)
Let y = 0
x + 0 = 3
x = 3
Another solution is (3, 0)
Therefore there are 2 solutions, namely (0, 3) and (3, 0)
