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Solve the system of equations.

 May 28, 2018

Best Answer 

 #1
avatar+971 
+3

If:

 

 \(y=x+6\\ y=x^2+8x+16\)

 

then: \(x+6=x^2+8x+16\)

 

\(x^2+7x+10=0\\ (x+2)(x+5)=0\\ x_1=-2, x_2=-5 \)

 

If x = -2, y = 4

 

If x = - 5, y = 1

 

I hope this helped,

 

Gavin

 May 29, 2018
 #1
avatar+971 
+3
Best Answer

If:

 

 \(y=x+6\\ y=x^2+8x+16\)

 

then: \(x+6=x^2+8x+16\)

 

\(x^2+7x+10=0\\ (x+2)(x+5)=0\\ x_1=-2, x_2=-5 \)

 

If x = -2, y = 4

 

If x = - 5, y = 1

 

I hope this helped,

 

Gavin

GYanggg May 29, 2018

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