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Solve the system of linear equations using any method.

$3x+y=\frac{1}{3}$

$2x-3y=\frac{8}{3}$

 Jan 7, 2021
 #1
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3(3x+y=1/3)

2x-3y=8/3

11x=11/3

\(x=1/3, y=-2/3\)

 Jan 7, 2021
 #2
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Hi Guest!

 

The easiest way to do this problem would be to graph it, and look for the point of intersection, x = 1/3, y = -2/3. 

 

However, I'm going to assume that you don't have a graphing calculator on hand. 

I'm going to try to make it so that the only x remains in the equation.  

 

3x + y = 1/3

2x - 3y = 8/3

 

One way to cancel out y in this equation, 2x - 3y = 8/3, is to add 3y. 

3x + y = 1/3

9x + 3y = 1

 

Then, we can just add. 

(9x + 3y) + (2x - 3y) = 1 + 8/3

11x = 11/3

x = 1/3

 

Knowing x, we can just plug it in for y. 

 

2(1/3) - 3y = 8/3

2/3 - 3y = 8/3

-3y = 6/3

y = -2/3

 

I hope this helped. :))))

=^._.^=

 Jan 7, 2021

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