Solve the system of linear equations using any method.

$3x+y=\frac{1}{3}$

$2x-3y=\frac{8}{3}$

Guest Jan 7, 2021

#2**0 **

Hi Guest!

The easiest way to do this problem would be to graph it, and look for the point of intersection, x = 1/3, y = -2/3.

However, I'm going to assume that you don't have a graphing calculator on hand.

I'm going to try to make it so that the only x remains in the equation.

3x + y = 1/3

2x - 3y = 8/3

One way to cancel out y in this equation, 2x - 3y = 8/3, is to add 3y.

3x + y = 1/3

9x + 3y = 1

Then, we can just add.

(9x + 3y) + (2x - 3y) = 1 + 8/3

11x = 11/3

x = 1/3

Knowing x, we can just plug it in for y.

2(1/3) - 3y = 8/3

2/3 - 3y = 8/3

-3y = 6/3

y = -2/3

I hope this helped. :))))

=^._.^=

catmg Jan 7, 2021