+0  
 
0
130
1
avatar

400g of 20%,240g of 43%and350g of 66% sulphuric acid are mixed .how much watershould be added to make a 10% solution of sulphuric acid?

Guest Dec 29, 2017
 #1
avatar+87293 
+1

If pure water is added, the  %  of   sulphuric acid   =   0%

 

So....we have the following equation :

 

400(.20)  + 240(.43)  + 350(.66)  +  0x =   .10(400 + 240 + 350  + x)

 

80  +  103.2  + 231    =   .10x  +  .10( 400 + 240  +  350)

 

414.2      =  .10x   +  .10(990)

 

414.2  =  .10x  +  99           subtract  99 from both sides

 

315.2  =  .10x        divide both sides by .10

 

3152  =  x

 

So.....3152g  of pure water should be added

 

 

cool cool cool

CPhill  Dec 29, 2017

13 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.