solve this equation

Solve the following system:
{2 x - 8 y = 56 | (equation 1)
6 x + 8 y = -88 | (equation 2)
Swap equation 1 with equation 2:
{6 x + 8 y = -88 | (equation 1)
2 x - 8 y = 56 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{6 x + 8 y = -88 | (equation 1)
0 x - (32 y)/3 = 256/3 | (equation 2)
Divide equation 1 by 2:
{3 x + 4 y = -44 | (equation 1)
0 x - (32 y)/3 = 256/3 | (equation 2)
Multiply equation 2 by 3/32:
{3 x + 4 y = -44 | (equation 1)
0 x - y = 8 | (equation 2)
Multiply equation 2 by -1:
{3 x + 4 y = -44 | (equation 1)
0 x+y = -8 | (equation 2)
Subtract 4 × (equation 2) from equation 1:
{3 x+0 y = -12 | (equation 1)
0 x+y = -8 | (equation 2)
Divide equation 1 by 3:
{x+0 y = -4 | (equation 1)
0 x+y = -8 | (equation 2)
Collect results:
Answer: |x = -4                and           y=-8  OR B

                                                2x - 8y  =    56

                                                6x + 8y  =  -88

Add down the columns:       8x           =  -32

         Divide by 8:                             x  =  -4

Replace the x-term in the first equation with -4:  2(-4) - 8y  =  56

Finish:                                                                           -8 - 8y  =  56

                                                                                           - 8y  =  64

                                                                                               y  =  -8