Solve for x over the real numbers:
2^(x^2 + 2 x - 15) = 1
Take the logarithm base 2 of both sides:
x^2 + 2 x - 15 = 0
The left hand side factors into a product with two terms:
(x - 3) (x + 5) = 0
Split into two equations:
x - 3 = 0 or x + 5 = 0
Add 3 to both sides:
x = 3 or x + 5 = 0
Subtract 5 from both sides:
Answer: |x = 3 or x = -5
