+0  
 
0
21
2
avatar

solve this indices equation 

2^(x−1) = 4^x/8

 
Guest Sep 16, 2018
 #1
avatar+12727 
+1

Take LOG of both sides to obtain:  (I  assume this is  :   2^(x-1) = 4^(x/8)      )

 

(x-1) LOG 2  = x/8 (LOG 4)    and solve for x

(x-1)(8/x) = LOG4/LOG2

8-8/x =2

-8/x = -6

x= 8/6

 
ElectricPavlov  Sep 16, 2018
edited by ElectricPavlov  Sep 16, 2018
 #2
avatar
0

Its 2

 
Guest Sep 16, 2018

7 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.