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solve this indices equation 

2^(x−1) = 4^x/8

 Sep 16, 2018
 #1
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Take LOG of both sides to obtain:  (I  assume this is  :   2^(x-1) = 4^(x/8)      )

 

(x-1) LOG 2  = x/8 (LOG 4)    and solve for x

(x-1)(8/x) = LOG4/LOG2

8-8/x =2

-8/x = -6

x= 8/6

 Sep 16, 2018
edited by ElectricPavlov  Sep 16, 2018
 #2
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Its 2

 Sep 16, 2018

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