solve this indices equation
2^(x−1) = 4^x/8
Take LOG of both sides to obtain: (I assume this is : 2^(x-1) = 4^(x/8) )
(x-1) LOG 2 = x/8 (LOG 4) and solve for x
(x-1)(8/x) = LOG4/LOG2
8-8/x =2
-8/x = -6
x= 8/6
Its 2
+36916 
