Solve this problem by substitution: x+3=y 3x+4y=7

0

1221

1

Solve this problem by substitution: x+3=y 3x+4y=7

Guest Nov 8, 2014

0 users composing answers..

Best Answer

+130511

+5

x+3=y

3x+4y=7

Note, if y = x + 3, just substitute this to the second equarion........so we have

3x + 4(x + 3) = 7 simplify

3x + 4x + 12 = 7

7x + 12 = 7 subtract 12 from both sides

7x = -5 divide by 7 on both sides

x = -5/7

CPhill Nov 8, 2014

1⁺⁰ Answers

+130511

+5

Best Answer

x+3=y

3x+4y=7

Note, if y = x + 3, just substitute this to the second equarion........so we have

3x + 4(x + 3) = 7 simplify

3x + 4x + 12 = 7

7x + 12 = 7 subtract 12 from both sides

7x = -5 divide by 7 on both sides

x = -5/7

CPhill Nov 8, 2014

2 Online Users