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How would you solve 3(2x+4)-2x=50, x=

 Apr 6, 2020
 #1
avatar+1968 
+3

Expand, combine like terms, and solve!

 Apr 6, 2020
 #2
avatar+201 
+2

x=18

 Apr 6, 2020
 #3
avatar+252 
0

Simplifying we get 6x+12-2x=50. Further we get 4x+12=50. SUbtract 12 on each side. 4x=38. x=9.5

 Apr 6, 2020
 #4
avatar+116 
+1

3(2x 4)-2x=50 x= 2

all you have to do is split the 3x^2 into 2x^2 and x^2,so the problem will look like this: x^3+2x^2 + X^2 -4. This can then be grouped as (x^3+2x^2)+(x^2-4). then, you have to pull an x^2 out of the first quantity and factor the second quantity. Since the second quantity is the difference of squares, it can be factored into 2

best answer smiley

 Apr 6, 2020
 #5
avatar+111329 
+2

3(2x + 4) -  2x   =  50

 

6x  +  12   - 2x   = 50

 

4x  + 12  = 50      subtract   12  from both sides

 

4x  = 38      divide both sides by  4

 

x  = 38/4 = 19/2  =   9. 5

 

 

cool cool cool

 Apr 6, 2020

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