h^2+6h-16=0
in order to factorise this you have to look for 2 numbers that multiply to -16 and add to 6
Since they mult to a negative - one must be neg and the other positive.
Since they add to a positive the |bigger one| must be positive.
The obvious solution then becomes +8 and -2
(x+8)(x-2)=0
Now continue with CPhill's method.
You must not be good at math. I was mighty good back in the day. I used to be able to figure out x without checkin the tech specs. You're not good enough to join me and the boys for "Joe's Math Bash" back in the Big Easy (Washington). Biden out.
Rewrite as h^2 + 6h - 16 = 0 factoring this, we have
(h + 8 ) (h - 2) = 0 Setting each factor to 0, we have
h = - 8 and h = 2
h^2+6h-16=0
in order to factorise this you have to look for 2 numbers that multiply to -16 and add to 6
Since they mult to a negative - one must be neg and the other positive.
Since they add to a positive the |bigger one| must be positive.
The obvious solution then becomes +8 and -2
(x+8)(x-2)=0
Now continue with CPhill's method.