solve this with factoring

2x^2 - 7x + 5 = 0.

2x^2 - 2x - 5x + 5 = 0. (In any formula ax^2+bx+c, find two numbers, m and n, where m+n = b and m*n = a*c).

2x(x-1) - 5(x-1) = 0. (Step 2: Separate the equation in two, and find the Highest Common Factor (in these cases, 2x and 5, respectively. Make sure the expressions in brackets match!)

(x-1)(2x-5) = 0. (Finally, remove the in-brackets expression from both halves, and place what remains in it's own bracket.)

And there you have it.

2x^2-7x+5=0   factor

(2x - 5) (x -1 )  =  0

Set each factor to 0

2x - 5  = 0                                     and                  x  - 1  = 0

add 5 to both sides                                              add 1 to both sides

2x = 5                                                                   x = 1

divide both sides b 2

x = 5/2

So.....the two answers are   x =5/2      and     x =  1