Solve the following system: {2 x+5 y = -24 | (equation 1) 3 x-5 y = 14 | (equation 2) Swap equation 1 with equation 2: {3 x-5 y = 14 | (equation 1) 2 x+5 y = -24 | (equation 2) Subtract 2/3 × (equation 1) from equation 2: {3 x-5 y = 14 | (equation 1) 0 x+(25 y)/3 = (-100)/3 | (equation 2) Multiply equation 2 by 3/25: {3 x-5 y = 14 | (equation 1) 0 x+y = -4 | (equation 2) Add 5 × (equation 2) to equation 1: {3 x+0 y = -6 | (equation 1) 0 x+y = -4 | (equation 2) Divide equation 1 by 3: {x+0 y = -2 | (equation 1) 0 x+y = -4 | (equation 2) Collect results: Answer: | | {x = -2 y = -4
