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-3x^2+4x+1=16x+13

Guest May 23, 2017
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-3x2 + 4x + 1 = 16x + 13

 

Add  3x2  to both sides of the equation.

4x + 1 = 3x2 + 16x + 13

 

Subtract  4x  from both sides of the equation.

1 = 3x2 + 12x + 13

 

Subtract 1 from both sides of the equation.

0 = 3x2 + 12x + 12

 

Now we can use the quadratic formula, with a = 3, b = 12, and c = 12, to solve for x.

\(x = {-12 \pm \sqrt{12^2-4(3)(12)} \over 2(3)} \\~\\ x = {-12 \pm \sqrt{144-144} \over 6} \\~\\ x = {-12 \pm \sqrt{0} \over 6} \\~\\ x = {-12\over 6} \\~\\ x = -2\)

hectictar  May 23, 2017

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