-3x2 + 4x + 1 = 16x + 13
Add 3x2 to both sides of the equation.
4x + 1 = 3x2 + 16x + 13
Subtract 4x from both sides of the equation.
1 = 3x2 + 12x + 13
Subtract 1 from both sides of the equation.
0 = 3x2 + 12x + 12
Now we can use the quadratic formula, with a = 3, b = 12, and c = 12, to solve for x.
\(x = {-12 \pm \sqrt{12^2-4(3)(12)} \over 2(3)} \\~\\ x = {-12 \pm \sqrt{144-144} \over 6} \\~\\ x = {-12 \pm \sqrt{0} \over 6} \\~\\ x = {-12\over 6} \\~\\ x = -2\)