Solve using zeros

I don't know any methods other than quad. eq. and sq. roots.

 

Solve using square roots

 

2x² +6 = 14

2x²=8

x²=4

x = $\pm2$

 

 

 

 

(x-1)² +3 = 12

(x-1)² = 9

x-1 = $\pm3$

either x = 4 or x= -2

 

 

Solve using any method

y = x²-3x+4

y = x+9

x² - 3x + 4 = x + 9

x²-4x-5 = 0

(x-5)(x+1) = 0

either x = 5 or x = -1

 

 

y = 2x²-4x+7

y=9

2x²-4x+7 = 9

2x²-4x-2 = 0

x²-2x-1 = 0

$x = {-(-2) \pm \sqrt{(-2)^2-4(1)(-1)} \over 2(1)}$= $1\pm\sqrt2$

either x = 1+√2 or x=1-√2

 

 

y=x²

y=1

x²=1

x=$\pm1$

either x=1 or x = -1

 

$y = x^2-1$

$y=\frac{1}{2x}-3$

$x^2-1=\frac{1}{2x}-3$

$x^3-x=\frac{1}{2}-3x$

$x^3+2x-\frac{1}{2}=0$

x=  0.24283973258548086 or x=  -0.12141986629274043 + 1.4297651386824481i or

x=  -0.12141986629274043 - 1.4297651386824481i