Solve (with steps please)
(1/3)^x=sqrt(27)
(1/3)^x=sqrt(27) we can rewrite this as
(3^-1)^x = 3*sqrt(3) simplify
(3)^(-x) = 3^1 * 3^(1/2)
3^(-x) = 3^(3/2) and since we have equal bases, we can solve for the exponents
-x = 3/2 multiply both sides by -1
So
x = -3/2