Loading [MathJax]/jax/output/SVG/jax.js

Solve without using the Quadratic Formula

0

833

2

+21

The Problem is:

$\\x^2+2x+1=5\\$

Which I then simplified to

$\\x^2+2x-4=0\\$

This problem has been giving me some real trouble. I can't find two numbers that multiply to -4 and add to 2.

I could really use some help. :)

Purpe Aug 16, 2015

Best Answer

+33654

+15

This doesn't have nice integer solutions.

You can express x² + 2x + 1 = 5 as (x + 1)² = 5

so x+1 = ±√5

so x = -1±√5

.

Alan Aug 16, 2015

2⁺¹ Answers

+33654

+15

Best Answer

This doesn't have nice integer solutions.

You can express x² + 2x + 1 = 5 as (x + 1)² = 5

so x+1 = ±√5

so x = -1±√5

.

Alan Aug 16, 2015

+21

+5

Thanks :)

I could not for the life of me figure out any way to solve it :)

Purpe Aug 16, 2015

0 Online Users