Solve x, y, and z

4xy^z+4 =6

4xy^z = 2

xy^z = 1/2 

 

Threre are INFINITE solutions to this...need more info....

\(4xy^z+4=6\\ 4xy^z=2\\ xy^z=\dfrac{1}{2}\\ x=\dfrac{1}{2y^z}\\ y^z=\dfrac{1}{2x}\\ y = \dfrac{1}{\sqrt[z]{2x}}\\ z\log y = -\log (2x)\\ z = -\dfrac{\log2x}{\log y}\)

.