1. Find all real numbers a that satisfy \frac{1}{64a^3 + 7} - 7 = 0. 2. Find all values of a that satsify the equation \frac{a}{3} + 1 = \frac{a + 3}{a} + 1.
(1) a = (-3/7)^(1/3)/2^(2/3) a = -(3/7)^(1/3)/2^(2/3) a = -((-1)^(2/3) (3/7)^(1/3))/2^(2/3)
(2)Results a = -3/2 (sqrt(5) - 1) a = 3/2 (1 + sqrt(5))
