1. Find all real numbers a that satisfy \frac{1}{64a^3 + 7} - 7 = 0.
2. Find all values of a that satsify the equation \frac{a}{3} + 1 = \frac{a + 3}{a} + 1.
+1306 1. Start by multiplying both sids of the equation by \(64a^3+7\) to get rid of the fraction. From there just do some regrouping to get the variable terms on one side and constant terms on the other.
2. Same here get rid of the fractions by multiplying the whole equation by the common denominator \(3a\), and from there just rearrange it and solve 
