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Five times a number is divided by 7 more than the number. If the result is 0, then what was the original number?

 May 27, 2023
 #1
avatar+274 
+2

Using the information given we can form an equation: 5x = 7+x. Now we solve for x:

 

5x = 7+x

5x-x = 7+x-x (subract x from both sides)

4x = 7 (combine the like terms)

x = \(\frac{7}{4}\) (divide by 4 to isolate x)

 

Now let's check our answer by plugging in the value of x to the question:

 

\(5 \cdot x = 5 \cdot \frac{7}{4} = \frac{35}{4} \)

\(\frac{7}{4}+7 = \frac{7}{4} + \frac{28}{4} = \frac{35}{4}\)

 

\(\frac{35}{4} - \frac{35}{4} = 0 \)

 May 27, 2023
 #2
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Read the question, it says that five times a number IS DIVIDED BY 7 more than the number, it doesn't say that five times a number is equal to 7 more than the number.

 May 28, 2023
 #3
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Let the number ==N

 

5N / [7 + N] =0

 

5N = 0

 

N = 0

 May 28, 2023
 #4
avatar+274 
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That's what I thought at first but I don't think you're correct.

 May 29, 2023

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