Five times a number is divided by 7 more than the number. If the result is 0, then what was the original number?
+274 Using the information given we can form an equation: 5x = 7+x. Now we solve for x:
5x = 7+x
5x-x = 7+x-x (subract x from both sides)
4x = 7 (combine the like terms)
x = \(\frac{7}{4}\) (divide by 4 to isolate x)
Now let's check our answer by plugging in the value of x to the question:
\(5 \cdot x = 5 \cdot \frac{7}{4} = \frac{35}{4} \)
\(\frac{7}{4}+7 = \frac{7}{4} + \frac{28}{4} = \frac{35}{4}\)
\(\frac{35}{4} - \frac{35}{4} = 0 \)
Read the question, it says that five times a number IS DIVIDED BY 7 more than the number, it doesn't say that five times a number is equal to 7 more than the number.
