Five times a number is divided by 7 more than the number. If the result is 0, then what was the original number?

Guest May 27, 2023

#1**+2 **

Using the information given we can form an equation: 5x = 7+x. Now we solve for x:

5x = 7+x

5x-x = 7+x-x (subract x from both sides)

4x = 7 (combine the like terms)

x = __\(\frac{7}{4}\)__ (divide by 4 to isolate x)

Now let's check our answer by plugging in the value of x to the question:

\(5 \cdot x = 5 \cdot \frac{7}{4} = \frac{35}{4} \)

\(\frac{7}{4}+7 = \frac{7}{4} + \frac{28}{4} = \frac{35}{4}\)

\(\frac{35}{4} - \frac{35}{4} = 0 \)

supremecheetah May 27, 2023

#2**0 **

Read the question, it says that five times a number IS DIVIDED BY 7 more than the number, it doesn't say that five times a number is equal to 7 more than the number.

Guest May 28, 2023