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*Find all values of x such that \sqrt{4x^2} + \sqrt{x^2} = 6 + 3x*.

I thought I had this figured out in an earlier posting of this same question,

but a moderator, Alan, added an answer, as a correction of the mistake

that I had made in my answer. Here's a copy/paste of what Alan said:

Note there is a difference between x^2 = 4, for which x = ±2, and x = √4, for which x = +2 only.

√(4x^2) = 2∣x∣ and √(x^2) = ∣x∣

so we have: 3∣x∣ = 6 + 3x

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Bosco Jun 28, 2023