4sin(x)^2*tan(x)=tan(x) = {x=0, x=-(((pi)/6)), x=((pi)/6)}
I think. Probably not though. :|
4 sin^2 x tan x = tan x subtract tan x from both sides
4sin^2x tanx - tan x = 0 factor out tan x
tanx [ 4sin^2x - 1 ] = 0
Set both factors to 0
tan x = 0 and this happnes at [ 0 ± n 180 ] degrees where ni is an integer
4sin^2 x = 1 divide both sides by 4
sin^2x = 1/4 take ± roots of both sides
sinx = ± √[ 1/4] = ± 1/2 and this happens at [ 30 ± n 180] degrees and at [ 150 ± n 180] degrees where n is an integer
Here's a graph : https://www.desmos.com/calculator/aeoqwikiz7