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Find the solutions to 16^x - 25*4^x + 24 = 0.

 Aug 22, 2020
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Find the solutions to 16^x - 25*4^x + 24 = 0.

 

Let  u = 4^x, so the equation becomes:

 

u^2 -25u +24 = 0 This factorises as  (u - 24)(u - 1) = 0  so u = 24 and u = 1

 

Hence we have 4^x = 24    and  4^x = 1

 

Can you take it from here?   (Think about taking logs of both sides)

 Aug 22, 2020

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