Solve for x: \frac(3x + 12)(x + 4) = (4x^2 + 8x + 18x^2)(2x).
\(\frac{3x + 12}{x + 4} = (4x^2 + 8x + 18x^2)(2x)\)
\(3=(4x^2 + 8x + 18x^2)(2x)\)
\(3=(2x)(22x^2+8x)\)
\(3=44x^3+16x^2\)
I'm afraid that's as far as I can get you.
