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Solve for x: \frac(3x + 12)(x + 4) = (4x^2 + 8x + 18x^2)(2x).

 May 5, 2023
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\(\frac{3x + 12}{x + 4} = (4x^2 + 8x + 18x^2)(2x)\)

\(3=(4x^2 + 8x + 18x^2)(2x)\)

\(3=(2x)(22x^2+8x)\)

\(3=44x^3+16x^2\)

I'm afraid that's as far as I can get you.

 May 5, 2023

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