We break \(27^x\) into \((3^3)^x\) , and \(9^4\) into \((3^2)^4\) . Now, we have \(3^2*3^8=3^{3x}\) . Since the bases are equal, we have \(3x=2+8, 3x=10, x=\boxed{\frac{10}{3}}\)
We break \(27^x\) into \((3^3)^x\) , and \(9^4\) into \((3^2)^4\) . Now, we have \(3^2*3^8=3^{3x}\) . Since the bases are equal, we have \(3x=2+8, 3x=10, x=\boxed{\frac{10}{3}}\)
