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# solveeeee

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Solve for x:

$$3^2*9^4=27^x$$

Apr 21, 2018

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We break $$27^x$$ into $$(3^3)^x$$  , and  $$9^4$$ into $$(3^2)^4$$ . Now, we have $$3^2*3^8=3^{3x}$$ . Since the bases are equal, we have $$3x=2+8, 3x=10, x=\boxed{\frac{10}{3}}$$

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Apr 21, 2018

We break $$27^x$$ into $$(3^3)^x$$  , and  $$9^4$$ into $$(3^2)^4$$ . Now, we have $$3^2*3^8=3^{3x}$$ . Since the bases are equal, we have $$3x=2+8, 3x=10, x=\boxed{\frac{10}{3}}$$