How to solve these algebraically?
Hello Guest!
a)
−2+5z−32=1335z−32=135z−32=27z−3=272z3=1272z=13√(33)2
z=19
!
b)
2,1x0,25+5=7x14=22,1x=(22,1)4
x=(2021)4=(22⋅53⋅7)4
x=28⋅5434⋅74=0,8227...
thank you so much !! very clear and was able to follow the steps :)
thank u so much !!