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# Solving for A

+2
213
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+804

If $$(4-a)^3 = 32$$, then what is $$a$$?

Answer is $$a = 4-2\sqrt[3]{4}$$.

I just need work finding the solution.

Jul 24, 2019

#1
+8853
+5

$$(4-a)^3\ =\ 32$$

Take the cube root of both sides of the equation.

$$\sqrt[3]{(4-a)^3}\ =\ \sqrt[3]{32}$$

Simplify the left side with the rule  $$\sqrt[3]{n^3}\ =\ n$$

$$4-a\ =\ \sqrt[3]{32}$$

We can rewrite  32  like this because  32 = 2 * 2 * 2 * 2 * 2

$$4-a\ =\ \sqrt[3]{2\cdot2\cdot2\cdot2\cdot2}$$

We can rewrite the right side again like this...

$$4-a\ =\ \sqrt[3]{2\cdot2\cdot2}\cdot\sqrt[3]{2\cdot2}$$

And   2 * 2 * 2  =  23   and   2 * 2  =  4

$$4-a\ =\ \sqrt[3]{2^3}\,\cdot\,\sqrt[3]{4}$$

Simplify  $$\sqrt[3]{2^3}$$  again with the rule  $$\sqrt[3]{n^3}\ =\ n$$

$$4-a\ =\ 2\,\cdot\,\sqrt[3]{4}$$

$$4-a\ =\ 2\sqrt[3]{4}$$

Add  a  to both sides of the equation.

$$4\ =\ 2\sqrt[3]{4}+a$$

Subtract  $$2\sqrt[3]{4}$$  from both sides of the equation.

$$4-2\sqrt[3]{4}\ =\ a$$

$$a\ =\ 4-2\sqrt[3]{4}$$-

Jul 24, 2019
#2
+1015
+1

Nice!

Nickolas  Jul 24, 2019
#3
+19845
0

(4-a)^3 = 32      cube root both sides   (note that 32 = 2^5 )

(4-a) = cubrt(2^5)      Simplify the right side

(4-a) = 2 cubrt(4)      Add 'a' to both sides and subtract 2 cubrt(4) from both sides

4- 2 cubrt(4) = a

Jul 24, 2019