Question: ∠5 is supplementary to ∠6. If m∠5 = ( x2 ) and m∠6 = ( 8x ), then find the measure of each angle.
I know to set it up as x2 + 8x = 180, but I'm not sure what to do once I reach x2 + x = 22.5.
Let's go this way
X^2 + 8x - 180 = 0
(x-10)(x+18) = 0 Now do you know where to go?