I can't figure out how to solve for ∫ sqrt(2x^2-4) / (7x). Can someone please help me?

2x^2-4>0

x^2-2>0

x^2>2

x>sqrt2 or x<-sqrt2

I have not worked it out but I am thinking that you could let \(\theta=sec^{-1}\frac{x}{\sqrt2}\)

that should help.

"I can't figure out how to solve for ∫ sqrt(2x^2-4) / (7x). Can someone please help me?"

Like so:

(As it is an indefinite integral you should add an arbitrary constant of course.)

.

Very nice, Alan!!!!