+0

# Solving Indefinite Integrals Of Square Root Functions

0
159
3

I can't figure out how to solve for ∫ sqrt(2x^2-4) / (7x). Can someone please help me?

Feb 26, 2019

#1
+103695
0

2x^2-4>0

x^2-2>0

x^2>2

x>sqrt2    or   x<-sqrt2

I have not worked it out but I am thinking that you could let    $$\theta=sec^{-1}\frac{x}{\sqrt2}$$

that should help.

Feb 26, 2019
edited by Melody  Feb 26, 2019
#2
+28135
+5

"I can't figure out how to solve for ∫ sqrt(2x^2-4) / (7x). Can someone please help me?"

Like so:

(As it is an indefinite integral you should add an arbitrary constant of course.)

.

Feb 26, 2019
edited by Alan  Feb 26, 2019
#3
+103131
0

Very nice, Alan!!!!

CPhill  Feb 26, 2019