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What is the solution to the equation 2(x35x2+11x)45=2x35(2x2+4x)+165?

 Dec 4, 2014

Best Answer 

 #1
avatar+128408 
+10

 2(x3−5x2+11x)−45=2x3−5(2x2+4x)+165      simplify

2x3 - 10x2 + 22x - 45 = 2x3 - 10x2 - 20x + 165         subtract/add 2x3, 10x2 to both sides

22x - 45  = -20x + 165        add 45 and 20 x to both sides

42x = 210        divide both sides by 42

x = 5

 

 Dec 4, 2014
 #1
avatar+128408 
+10
Best Answer

 2(x3−5x2+11x)−45=2x3−5(2x2+4x)+165      simplify

2x3 - 10x2 + 22x - 45 = 2x3 - 10x2 - 20x + 165         subtract/add 2x3, 10x2 to both sides

22x - 45  = -20x + 165        add 45 and 20 x to both sides

42x = 210        divide both sides by 42

x = 5

 

CPhill Dec 4, 2014
 #2
avatar+961 
+5

Thank u

 Dec 4, 2014

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