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How do you, using elimination, solve 6x+4y=34 and 6x+15y=78?

 Sep 25, 2017
 #1
avatar+98044 
+2

 6x+4y=34        multiply through by  -1   →    -6x  - 4y  - 34       (1)

 6x+15y=78          (2)

 

Add (1)  and (2)   and we get

 

11y  = 44    divide both sides by 11

y  = 4

 

Put this into any equation to solve for x

 

6x + 4(4)   = 34

6x + 16  = 34   subtract 16 from both sides

6x  = 18     divide both sides by 6

x  = 3

 

 

 

cool cool cool

 Sep 25, 2017
 #2
avatar+319 
+2

Good Job CP (Your new nickname lmao) You have done it once more again ^^... You are very nice to help people out with their math problems ^^ Good Job CP

knownhappyman68  Sep 25, 2017

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