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Here's the equation: \({|x+3 |} = 2\)

I made a table of values (this is not obviously correct):

(-3, 2)

(-2, 1)

(-1, 0)

(0, -1)

and plotting them on a graph, it gave me a slanting line.

 

However, I used desmos to graph \({|x+3 |} = 2\) and I got two verticle lines...

 

What did I do wrong?

 May 6, 2018
edited by Guest  May 6, 2018
 #1
avatar+988 
+3

Desmos is correct.

 

\(|x+3|=2 \\\text{should not be a slanted line because both} \\(x+3) \text{and}-(x+3) \text{is equal to 2} \)

 

To solve:

 

\((x+3)=2 \\ x=-1\)

 

\(-(x+3)=2 \\ -x-3=2 \\ -x=5 \\ x=-5\)

 

Two vertical lines, x = -1, and x = -5 is the graph of your equation. 

 May 6, 2018

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