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If x is a positive integer, what is the value of x for the equation (x!-(x-3)!) ÷ 23=1 ?

 Aug 17, 2020
 #1
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x = 4

4! =24

(4 - 3)! =1

24 - 1 = 23

23 / 23 =1

 Aug 17, 2020
 #2
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x! - (x-3)! = 23

 

x!    and     (x-3)!   have a difference of 23

 

x(x-1)(x-2)(x-3)(x-4)....     -   (x-3)(x-4).....

 

x = 4      just by looking at it......not sure how to do it mathematically...  frown

 Aug 17, 2020
 #3
avatar+273 
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Good work!

 Aug 17, 2020

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