If x is a positive integer, what is the value of x for the equation (x!-(x-3)!) ÷ 23=1 ?
x! - (x-3)! = 23
x! and (x-3)! have a difference of 23
x(x-1)(x-2)(x-3)(x-4).... - (x-3)(x-4).....
x = 4 just by looking at it......not sure how to do it mathematically...