Let f(x)= (3x-7)/(x+1)
Find the domain of f. Give your answer in interval notation.
Let f(x)=3(x-6)^2 +1. What is the range of f? Express your answer with interval notation
The demoinator of a fraction can't be 0 or negative, so anything less than or equal to -1 will be imposible.
There is no limit to the range of f(x) since x will always get bigger, but the minimum for the square is 0, so the minimum answer is 1.
I hope this helped. :)))