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# Some Questions, please elaborate. thanks

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1.How many ways are there to put 6 balls in 3 boxes if the balls are not distinguishable but the boxes are?

2. How many ways are there to put 6 balls in 3 boxes if the balls are distinguishable but the boxes are not?

3. How many ways are there to put 6 balls in 3 boxes if three balls are indistinguishably white, three are indistinguishably black, and the boxes are distinguishable?

Mar 17, 2019

#1
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1. My favorite type of problem! Get ready for Stars and Bars! To read more about "Stars and Bars," check here: https://math.stackexchange.com/questions/910809/how-to-use-stars-and-bars

Anyway, when we plug \(n=6\) and \(k=3\)\(\), we have \(\binom{6+3-1}{3-1}=\binom{8}{2}=4*7=\boxed{28}.\)

2. We break this up into cases. To create 6, with three numbers, we can use: 6-0-0, 5-1-0, 4-2-0, 4-1-1, 3-3-0, 3-2-1, and. 2-2-2.

6-0-0: Only one way

5-1-0: Take the ball that is alone, so 6 ways.

4-2-0: 6C2=15 ways for the two balls in their own box.

4-1-1: Again 15 ways, pick two of the six balls, but they cannot go in the box of 4.

3-3-0: 5C2=10 ways, by selecting two of the remaining five balls.

3-2-1: 6*10=60 ways by picking any of the six balls to be by itself.

2-2-2: 15 ways? First, you think they are distinguishable, yet you overcount by a factor 3!=6.

Thus, adding them all up, we get \(1 + 6 + 15 + 15 + 10 + 60 + 15 = \boxed{122}. \)

3. Try this on your own! Hint: Just multiply by the same number of outcomes of the white balls for the black balls!

Mar 17, 2019
#2
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Can you also solve this? How many ways are there to put 6 balls in 3 boxes if the balls are not distinguishable and neither are the boxes?

Mar 17, 2019
#3
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Sure. Here, we are dealing with indistinguishable balls and indistinguishable boxes.

Now, we have to count the number of ways to separate the six balls in three boxes.

We can have 6-0-0, 5-1-0, 4-2-0, 4-1-1, 3-3-0, 3-2-1, and 2-2-2, so there are \(\boxed{7}\) ways.

tertre  Mar 17, 2019
#4
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:)

Guest Mar 17, 2019
#5
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Thanks, tertre....these are always difficult   !!!

And

Nice pic, guest  !!!

Mar 17, 2019
#6
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Thanks ChPill!!

I agree w/ you that these problems are not diificult.

Guest Mar 17, 2019
#7
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Thank you, CPhill!

tertre  Mar 17, 2019