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Compute \[\frac{1}{2^3 - 2} + \frac{1}{3^3 - 3} + \frac{1}{4^3 - 4} + \dots + \frac{1}{100^3 - 100}.\]

 

I suspect the rule to be the start to be 1, the end to be 100 and the rule to be 1/(n^3-n)

 Dec 2, 2020
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listfor(n, 2, 10, (1 / (n^3 - n))==1 / 6,   1 / 24,   1 / 60,   1 / 120,   1 / 210,   1 / 336,   1 / 504,   1 / 720, 1 / 990............1 / 999,900==It converges to==5049 / 20,200

 Dec 2, 2020

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