Factorise:
v) (l+m)^2 - (l-m)^2
we need to expand this to solve but idk somehow I'm getting a wrong answer!
Your wish is my command Rosala :)
(l+m)^2 - (l-m)^2 Yuk Mmm
$$\\(l+m)^2 - (l-m)^2\\l^2+m^2+2lm-[l^2+m^2-2lm]\\l^2+m^2+2lm-l^2-m^2+2lm\\2\;lm+2\;lm\\4\;lm$$
This is fully simplified - there is nothing to factorise
Thank you so much Melody! I got my problem!thanks!
That is really good - that is what we are here for :)
Yeah! I know! Thanks!
(l+m)^2-(l-m)^2=(l+m+l-m)(l+m-l+m)=2l*2m=4ml
a^2-b^2=(a+b)(a-b)
Here's another way to do this one, rosala
(l+m)^2 - (l-m)^2
[ (l + m) - (l - m) ] [ (l + m) + (l - m)] =
[2m] [2l ]=
4ml
+11912 
