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(something) * (x-5) = x^2 - 25

I need to know that something

 Mar 15, 2020
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let that something be \(y\) 

so,

\(y*(x-5)=x^2-25\)

Notice that the right-hand side (after the equal) 

can be factorized into 

\((x-5)(x+5)\) since it is a difference between two squares.

So now we have

\(y*(x-5)=(x-5)(x+5)\) Divide both sides by \((x-5)\)

\(y=(x+5)\)

that "something" is \((x+5)\)

 Mar 15, 2020

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