The graph of $y = h(x)$ is shown in red below. Compute $h(h(7))$.
(Assume grid lines are spaced 1 unit apart.)
h(7) = 5
(The point (7,5) is on the graph)
So
h ( h(7) ) = h (5)
And h(5) = -1
(The point (5,-1) is on the graph )
h (h(7)) = h (5) = -1
Thank you CPhill
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