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SORRY, CORRECTION!!!!

 

Set   a=6 - 4sqrt(2),     y=Sqrt(2) - 1,   n=0, 1, 2, 3.........etc.    Iterate the following..........

 

y=[1 - (1 - y^4)^1/4] / [ 1 + (1 - y^4)^1/4], then:

a=a(1 + y)^4 - [2^(2n+3). y(1 + y +y^2)]..........converges to what?.

 Jan 16, 2016

Best Answer 

 #2
avatar+118723 
+5

You already asked this question here

 

http://web2.0calc.com/questions/convergence-to-what

 

Was the first one incorrect?

 

Why didn't you continue it over there - you can do that with a new post that gives the address of the old post. Like I just di.

 

You are obviously old enough and intelligent to learn.  Please do not do this again.     angry

 Jan 17, 2016
 #1
avatar
+5

1st. iteration:0.3183098869 3116115102 9133158227 1859818425 3271454241 5867324370 79998

2nd.iteration:0.3183098861 8379067153 7767526745 0287240689 2483588666 9511161849 04229

 

It is obvious that this formula converges very rapidly to 1/pi. While the 1st. iteration has only about 8 accurate digits, the 2nd. iteration has no less than 40 accurate digits of 1/pi. It is converging quartically, or order 4. That is, each iteration quadruples the accurate number of digits of 1/pi.

 Jan 16, 2016
 #2
avatar+118723 
+5
Best Answer

You already asked this question here

 

http://web2.0calc.com/questions/convergence-to-what

 

Was the first one incorrect?

 

Why didn't you continue it over there - you can do that with a new post that gives the address of the old post. Like I just di.

 

You are obviously old enough and intelligent to learn.  Please do not do this again.     angry

Melody Jan 17, 2016

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