Given a0=1and a1=5and the general relation a2n−an−1an+1=(−1)n for n≥1 find a3
im nor sure on how to start this problem...
any help well be appreciated!
thank you!!
For n = 1: a12 - a0·a2 = (-1)1 ---> (5)2 - 1·a2 = -1
---> 25 - a2 = -1
- a2 = -26
a2 = 26
For n = 2: a22 - a1·a3 = (-1)2 ---> 262 - 5·a3 = 1
You'll need to finish ...