sorta stuck

Question

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Given $a_0 = 1$ and $a_1 = 5$ and the general relation $a_n^2 - a_{n - 1} a_{n + 1} = (-1)^n$
for $n \ge 1$ find $a_3$

im nor sure on how to start this problem...

any help well be appreciated!

thank you!!

Guest Feb 22, 2022

geno3141 · Answer 1 · 2022-02-22T07:51:52

For n = 1: a₁² - a₀·a₂ = (-1)¹ ---> (5)² - 1·a₂ = -1

---> 25 - a₂ = -1

- a₂ = -26

a₂ = 26

For n = 2: a₂² - a₁·a₃ = (-1)² ---> 26² - 5·a₃ = 1

You'll need to finish ...