Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are .
A (5,-4)
B (5,-2)
C (10,-4)
D (10,-2)
If point D divides in the ratio 4 : 5, the coordinates of point D are .
A (62/9,-4)
B (58/9,-4)
Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are .
I'm assuming that C divides AB in the ratio of 3 : 2
We have 5 equalline segments on AB and C are 3 of these
We can find the x coordinate of B, thusly :
[ -6 + (3/5) ( x coordinate of B - - 6 ] = 3.6 add 6 to both sides
(3/5)(x coordinate of B + 6 ) = 9.6 multiply both side by (5/3)
x coordinate of B + 6 = 16 subtract 6 form both sides
x coordinate of B = 10
Similarly, we can find the y coordinate of B thusly.....
[ 5 + (3/5)( y coordinate of B - 5) = -0.4 subtract 5 from both sides
(3/5) (y coordinate of B - 5) = -5.4 multiply both sides by 5/3
y coordinate of B - 5 = -9 add 5 to both sides
y coordinate of B = -4
So....B = ( 10 , - 4) ⇒ "C"
See the graph, here : https://www.desmos.com/calculator/hfo8kkx0lp