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A circle is drawn that intersects all three sides of \(\triangle{PQR}\) as shown below. Prove that if \(AB=CD=EF\), then the center of the circle is the incenter of \(\triangle{PQR}\).

 

 Sep 24, 2017
 #1
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https://web2.0calc.com/questions/a-circle-is-drawn-that-intersects-all-three-sides-of-triangle-pqr-as-shown-below-prove-that-if-ab-cd-ef-then-the-center-of-the-circle-is-the

 Sep 24, 2017
 #2
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Thanks, AdminMod....I knew it looked familiar....LOL!!!!!

 

 

cool cool cool

 Sep 24, 2017

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