In a certain isosceles right triangle, the altitude to the hypotenuse has length 8. What is the area of the triangle?
We have the following relationship
(1/2) hypotenuse length / 8 = 8 / ( 1/2) hypotenuse length
cross-multiply
[(1/2) hypoenuse length] ^2 = 8 * 8
[(1/2) hypotenuse ]^2 = 64 take the sqrt of both sides
(1/2) hypotenuse length = 8
Area = (1/2) hypotenuse length * altitude = 8 * 8 = 64