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How many grams of water would require 2200 joules of heat to raise its temperature from 34*C to 100*C? The specific heat of water is 4.184 J/g*C

Guest May 22, 2017
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Energy change = mass*specific heat*temperature rise

 

2200 = mass*4.184*(100 - 34)

 

mass = 2200/(4.184*66) grams ≈ 7.97 grams

Alan  May 22, 2017

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