A policeman is 834 feet behind a car travling 25 mph, how fast does the policeman need to go to catch up to the car before the car travels 1500 more feet?
+23247 Let's calculate how much time it will take the car to cover the next 1500 feet.
It's speed is 25 mi/hr which is 25 x 5280 ft/hr = 132,000 ft/hr.
D = r·t ---> 1500 ft = 132,000 ft/hr x t
---> t = 1500/132,000 hr = 0.011363636... hr or 0.681818... min or 40.91 sec.
The peace officer must travel 1500 feet + 834 feet in that same time (which is 2334 feet)
D = r·t ---> 2334 ft = r x 0.011363636 hrs
---> rate = 2334 ft / 0.01136363 hrs ---> rate = 205,392 ft/hr
Dividing this by 5280 to get into miles per hour ---> 38.9 mi/hr.
+23247 Let's calculate how much time it will take the car to cover the next 1500 feet.
It's speed is 25 mi/hr which is 25 x 5280 ft/hr = 132,000 ft/hr.
D = r·t ---> 1500 ft = 132,000 ft/hr x t
---> t = 1500/132,000 hr = 0.011363636... hr or 0.681818... min or 40.91 sec.
The peace officer must travel 1500 feet + 834 feet in that same time (which is 2334 feet)
D = r·t ---> 2334 ft = r x 0.011363636 hrs
---> rate = 2334 ft / 0.01136363 hrs ---> rate = 205,392 ft/hr
Dividing this by 5280 to get into miles per hour ---> 38.9 mi/hr.
