A plane and a sphere intersect, and the intersection is a circle with area 48 pi. The plane has a distance of 3 units from the center of the sphere. Find the surface area of the sphere.
That guy is wrong and posting random stuff, real answer is 228pi beacuse using pythagorean theorem, we get sqrt(48+9) is the radius of circle. Since the surface area of a sphere is 4pi*r^2, we get 228pi as our desired answer. My aops is doctorpi btw
That guy is wrong and posting random stuff, real answer is 228pi beacuse using pythagorean theorem, we get sqrt(48+9) is the radius of circle. Since the surface area of a sphere is 4pi*r^2, we get 228pi as our desired answer. My aops is doctorpi btw
