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A plane and a sphere intersect, and the intersection is a circle with area 48 pi. The plane has a distance of 3 units from the center of the sphere.
Find the surface area of the sphere.

 Feb 3, 2020

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That guy is wrong and posting random stuff, real answer is 228pi beacuse using pythagorean theorem, we get sqrt(48+9) is the radius of circle. Since the surface area of a sphere is 4pi*r^2, we get 228pi as our desired answer. My aops is doctorpi btw

 Feb 5, 2020
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The surface area of the sphere is 64*pi.

 Feb 4, 2020
 #2
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+1
Best Answer

That guy is wrong and posting random stuff, real answer is 228pi beacuse using pythagorean theorem, we get sqrt(48+9) is the radius of circle. Since the surface area of a sphere is 4pi*r^2, we get 228pi as our desired answer. My aops is doctorpi btw

Guest Feb 5, 2020

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