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A steady force of 6 N applied to a spring stretches the spring 0.2 m. What is the spring's stiffness, k?

 Sep 21, 2016
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The equation for force of a spring is F = -k(delta x)

 

In this problem, the force is 6 N, and the displacement (delta x) is 0.2 m ----> 6 N = -k * 0.2 m

 

Now just use algebra to isolate k on one side of the equation.

 

-k = 6 N/0.2 m = 30 N/m

 

k = -30 N/m

 Sep 21, 2016

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