sqaure root of 2x times square root of 64x
\(\sqrt{2x}\times \sqrt{64x}\) = \(\sqrt{2\times 64x^{2} }= 8x\times \sqrt{2} \)
= 11.3137x
\(\sqrt{2x}\times \sqrt{64x}\\ = \sqrt{2}\times \sqrt{x}\times \sqrt{64}\times \sqrt{x}\\ = 8\times \sqrt{2}\times (\sqrt{x})^2\\ =8\sqrt2\;x\)
Same as asinus's answer.
