sqrt(0.5(x^2-9x+22))=0

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718

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Guest Mar 5, 2015

+118723

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Best Answer

$$\\\sqrt{0.5(x^2-9x+22)}=0\\\\
x^2-9x+22=0\\\\
\triangle=81-88<0$$

Since the determinant is less than 0 this equation is never true. There are no solutions.

Melody Mar 6, 2015

Melody · Answer 1 · 2015-03-06T10:19:24

$$\\\sqrt{0.5(x^2-9x+22)}=0\\\\
x^2-9x+22=0\\\\
\triangle=81-88<0$$

Since the determinant is less than 0 this equation is never true. There are no solutions.